with equal probability ,the observations 5,10,8,2 and 7 shows the no of defective units found during 5 inspections in a laboratory. Find mean and variance.
Answers
Given : the observations 5,10,8,2 and 7 shows the no of defective units found during 5 inspections in a laboratory.
To Find : Mean
Solution:
observations 5,10,8,2 and 7
Mean = ( 5 + 10 + 8 + 2 + 7 )/ 5 = 6.4
xi xi - Mean (xi - Mean)²
5 -1.4 1.96
10 3.6 12.96
8 1.6 2.56
2 -4.4 19.36
7 0.6 0.36
37.2
Variance = 37.2/5 = 7.44
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