Math, asked by Sushantbari2006, 9 months ago

with explanation only​

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Answered by divyamyindia271
0

Answer:

x = 3 -  \sqrt{8}  \\   \frac{1}{x} =  \frac{1}{3 -  \sqrt{8} }   \\  \frac{1}{x}  =  \frac{1}{3 -  \sqrt{8} }  \times  \frac{3 +  \sqrt{8} }{3 +  \sqrt{8} }  \\  \frac{1}{x}  =  \frac{3 +  \sqrt{8} }{ {3}^{2}   -    { \sqrt{8} }^{2} }  \\  \frac{1}{x}  = 3 +  \sqrt{8}

x = 3  -   \sqrt{8}  \\  {x}^{4}  =   {( {3 -  \sqrt{8}) }^{2} )}^{2}  \\  {x}^{4}  =  {(9 + 8 - 6 \sqrt{8} )}^{2}  \\  {x}^{4}  =  {(17 - 6 \sqrt{8}) }^{2}  \\  {x}^{4}  = 284  -  204 \sqrt{8}  + 288 \\  {x}^{4}  = 572 - 204 \sqrt{8}

  \frac{1}{x}  = 3 +  \sqrt{8}  \\   \frac{1}{ {x}^{4} }   = 572 + 204 \sqrt{8}

 {x}^{4}  +  \frac{1}{ {x}^{4} }  \\ 572 - 204 \sqrt{8}  + 572 + 204 \sqrt{8}  \\ 1144

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