Question

with explanation plz

Answer 1

Hy..
Friend...

....Here your answer....

m= 0.4 kg     h1 = 5m   g = 10 m/s^2
                     h2 = 20 m
Velocity of the ball after dropping 5m :  u
Velocity of the ball after being hit by the bat:  v
u² = 2 g h1  =>  u = √(2*10*5) = 10 m/s  (downwards)
v² = 2 g h2 = (2 *10 *20)   =>  v = 20 m/s  (upwards)

change of momentum = impulse = m(v+u) = 12 kg-m/s
Force = 100 N = 12 / t
t = time of contact = 0.12 sec

Thankyou
Brainly user...