Question

With full explanation =brainlest answer. Step wise​

Answer 1

Answer:

It's tricky but let explain you

Step-by-step explanation:

n=11

(a1+a11)/2 = 30. (a1+a11)= 60.

Sum of AP = n(a1+a11)/2. = 11*60/2. = 11*30.

= 330.

SUM OF THE 11TH TERMS IS 330.

Answer 2

Answer

330

Step-by-step explanation:

n = 11

so middle  term is 6 th term

let a be first term

let d be be the common difference

$t_{6} = 30 =a+ 5d$

$S_{11} = 11/2[t_{1}+t_{11} ]\\ =11/2[a +a +10d ]= 11/2[2a+10d]]\\ =11[a+5d] = 11[30] =330$