Question

with full solution...

Answer 1

we know that
$\sin( \alpha ) = opposite \: side \div hypotenuse \: side$
but given
$\sin( \alpha ) = a \div b$
so adjacent side =
$\sqrt{ {b}^{2} - {a}^{2} }$
now
$\cos( \alpha ) = \sqrt{ {b}^{2} - {a}^{2} } \div b$
and
$\tan( \alpha ) = a \div \sqrt{ {b}^{2} - {a}^{2} }$
hope this helps you
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