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1)since it is a parallelogram
so,AD=CB (as opp. sides are parallel and equal)
AB=DC(same reason,given above)
AC=AC(common)
Hence,by S.S.S
triangle ADC is congruent to triangleCBA
2)BY C.P.C.T
angleADC=angle CBA
3)By C.P.C.T
angle DAC=angleBCA
so,AD=CB (as opp. sides are parallel and equal)
AB=DC(same reason,given above)
AC=AC(common)
Hence,by S.S.S
triangle ADC is congruent to triangleCBA
2)BY C.P.C.T
angleADC=angle CBA
3)By C.P.C.T
angle DAC=angleBCA
2Shashank1111:
Nyc answered yr..
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