with median has a base calculate mean deviation and compare the variability of the two series A&B
series A: 3484, 4572, 4124, 3682, 5624, 4388, 3680, 4308
series B: 487, 508, 620, 382, 408, 266, 186, 218
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Answer:
Series A:-
Mean
=
¯¯¯¯¯
X
A
=
∑
X
A
N
=
140
7
=
20
Mean Deviation (Series A) =
∑
|
D
|
N
=
44
7
=
6.28
Coefficient of M.D (Series A) =
M
.
D
¯¯¯¯
X
A
=
6.28
20
=
0.31
Series B:-
Mean
=
¯¯¯¯¯
X
B
=
∑
X
B
N
=
175
7
=
25
Mean Deviation (Series B) =
∑
|
D
|
N
=
46
7
=
6.57
Coefficient of M.D (Series B) =
M
.
D
¯¯¯¯
X
B
=
6.57
25
=
0.26
Since coefficient of mean deviation for series A is more than that of series B, we can say that series A has greater variability as compared to series B.
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