Question

with ' n' parallal plates each of same area
A and separated by equal distance d with air
or vacuum between the plates, what is the
effective capacity?​

Answer 1

Answer:

they are capacitors in series

which is like resistor in parallel

1/ Ceff = summation 1/Ci

where Ci is capacitance of ith capacitoe

now Ci = ëA/d

hence summation 1/ci

for n 2 it is 1 capacitor.

for n3 it is 2 capacitors

for n = n it is n-1 capacitors

hence Ceff = ëA/d(n-1)