Math, asked by poojasharda5953, 11 months ago

With p starting the work, working on alternate days, p and q can finish a work in 17 days. If q works on the first day and q and p work alternately, the work is finished in 53/3 days. How many days will each take individually to execute the work?

Answers

Answered by amitnrw
6

Answer:

Q will finish in 35 days

P will finish in  35/3  Days

Step-by-step explanation:

Lets say P's 1 day work  = P

& Q's 1 day work = Q

With p starting the work, working on alternate days, p and q can finish a work in 17 days.

=> P works for 9 days  & Q works for 8 days

Work done = 9P + 8Q

If q works on the first day and q and p work alternately, the work is finished in 53/3 days

53/3 = 17 + 2/3 Days

=> Q works  for 9 Days  & P work for 8 + 2/3  = 26/3 Days

Work done = 9Q + 26P/3

9P + 8Q = 9Q + 26P/3

=> Q = P/3

=> P = 3Q

Work Done = 9P + 8Q  = 27Q + 8Q = 35Q

Q will finish in 35 days

P will finish in  35/3  Days

Answered by SBitupan
0

Step-by-step explanation:

9P+8Q=TW=9Q+8⅔P

⅓P=Q

P:Q=3:1 (eff)

Day's they Required to complete will be in the ratio 1:3

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