Question

With reference to the above schematic representation of (a) Spermatogenesis and (b) Oogenesis answer the following questions:
a.) About 300 million spermatozoa may be present in a human male ejaculation at one time. Calculate how many spermatocytes will be involved to produce 300 spermatozoa.
b.) How many chromatids are found during Oogenesis in (i) Primary oocyte and (ii) First polar body in a human female?

Answer 1

Answer:

Each primary spermatocyte will undergo meiosis-I and meiosis-2 which will result in 4 spermatozoa 300 million/4 = 75 million (b) Since replication has occurred by this stage 46 x 2 = 92 chromatids Meiosis –I is completed by this time 92/2 = 46 chromatids

Explanation:

Answer 2

To produce 300milliom spermatozoa the total number of spermatocytes that are needed is equal to 75million.

Explanation:

• From one spermatocytes the number of spermatozoa that are produce is four time. This is due to meiosis which produces 4cells per complete division.

• The number of chromatids which are found during oogenesis is equal to 92 in case of the first polar body release.

• However this number becomes equal to 46 after the release of the first polar body.

To know more about oogenesis,

Explain the role of hormones that control oogenesis - Brainly.in

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