Question

with solution .............​

Answer 1

f(x)=6x2-11x3+ax-20

f(4/3)=6(4/3)3-11(4/3)2+a(4/3)-20

0=6(64/27)-11(16/9)+4a/9-20

0=2(64/9)-(176/9)+4a/3-20

0=128/9-176/9+4a/3-20

0=-48/9+4a/3-20

0=-16/3+4a/3-20

20=4a-16/3

20*3=4a-16

60=4a-16

60+16=4a

4a=76

a=76/4

a=19