Question

with solution and explanation ​

Answer 1

Answer:

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Answer 2

Answer:

14. ✓3 tan 2∆ - 3 = 0

tan 2∆ = 3/✓3

tan 2∆ = (1/✓3) × 3

2∆ = tan-¹(1/✓3) × 3

2∆ = π/6 × 3

∆ = 3π/12

∆ = π/4

15. P(E) + P(E¹) = 1