Question

with step wise .if not. then ur ans. will be deleted.
​

Answer 1

Answer:

Probability that 1 egg is bad

According to each case

$= \frac{2}{12} \times \frac{10}{11} \times \frac{9}{10} + \frac{10}{12} \times \frac{2}{11} \times \frac{9}{10} + \frac{10}{12} \times \frac{9}{11} \times \frac{2}{10} \\ \\ = 3 \times \frac{2 \times 10 \times 9}{10 \times 11 \times 12} \\ = \frac{18}{44}$

You could also directly compute

$\binom{3}{1} \frac{2 \times 10 \times 9}{12 \times 11 \times 10}$

Probability that two eggs are bad

$\binom{3}{2} ( \frac{2}{12} \times \frac{1}{11} \times \frac{10}{10} ) = \frac{1}{22}$