Math, asked by srihari72120806, 10 months ago

with steps pls..........​

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Answered by ksonakshi70
0

Answer:

 \frac{2 \sqrt{3} -  \sqrt{5}  }{2 \sqrt{2}  + 3 \sqrt{3} }  =   \\  = \frac{2 \sqrt{3} -  \sqrt{5}  }{2 \sqrt{2} + 3 \sqrt{3}  }  \times  \frac{2 \sqrt{2}  - 3 \sqrt{3} }{2 \sqrt{2} - 3 \sqrt{3}  }  \\  =   \frac{2 \sqrt{3} (2 \sqrt{2} - 3 \sqrt{3} ) -  \sqrt{5} (2 \sqrt{2}   - 3 \sqrt{3} )}{(2 \sqrt{2}) {}^{2}  - (3 \sqrt{3}  ) {}^{2} }  \\  =  \frac{4 \sqrt{6}  - 18 - 2 \sqrt{10} +  3 \sqrt{15}  }{8 - 27}  \\  =  \frac{4 \sqrt{6}  + 3 \sqrt{15} - 2 \sqrt{10}   - 18}{ - 15}

Answered by Anonymous
1

Answer:

Hey mate your answer is given below

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