Question

with that horizontal velocity should a body be thrown so that it may more parallel to the surface of the earth along the equator ? The radius of the earth at the equator is 6400 km and g = 9.7m/s². please give correct answer incorrect answer will be reported .........​

Answer 1

Answer:

object is thrown parallel to the surface of earth and velocity is tangential at equator

then we will have

F_{net} = F_cF

net

=F

c

mg = \frac{mv^2}{R}mg=

R

mv

2

by solving above equation we will have

g = \frac{v^2}{R}g=

R

v

2

v^2 = Rgv

2

=Rg

v = \sqrt{Rg}v=

Rg

v = \sqrt{6400*10^3 * 9.7}v=

6400∗10

3

∗9.7

v = 7.88 * 10^3m/sv=7.88∗10

3

m/s

so object will move with above speed

Explanation:

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Answer 2

Answer:

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