Question

with the help of a diagram describe an experiment to verify Archimedes principle​

Answer 1

Answer:

Explanation:

Experiment to verify Archimedes' principle:

∙ Suspends a solid by a thin thread from the hook of a balance. Make note of its weight.

∙

Fill a eureka can with water up till its spout. St up a cylinder below the spout of the eureka as observed in the diagram. Gently, submerged the solid in water and collect the displaced water in the measuring cylinder.

∙ Make note of the weight of the liquid and the volume of the water is assemble in the measuring cylinder once the water dripping through the spout.

∙ It is clear from the diagram that the volume of the water displaced is equivalent to the difference of weight in air to the weight in water i.e.,

Weight in air-weight in water - volume of water

300gf−200gf=100gf

 Volume of water displaced is equal to the volume of solid which is equivalent to 100cm  3

 As we known that the density of water is 1 gcm  −3

  Hence the weight of the water displaced is equivalent to the loss in weight or the upthrust =100gf

 Hence the Archimedes' principle is verified.