With the help of balanced chemical equations, explain the formation of Sulphuric acid.
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Answered by
1
Answer:
SO
3
is converted to Sulphuric acid in the contact process by dissolution in 98% sulphuric acid to form oleum (H
2
S
2
O
7
) followed by dilution of oleum with water.
SO
3
+H
2
SO
4
→H
2
S
2
O
7
H
2
S
2
O
7
+H
2
O→2H
2
SO
4
Answered by
1
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