Question

with the help of circuit
diagram explain the working of full waverectifier​

Answer 1

Explanation:

Power Diodes can be connected together to form a full wave rectifier that convert AC voltage into pulsating DC voltage for use in power supplies

In a Full Wave Rectifier circuit two diodes are now used, one for each half of the cycle. A multiple winding transformer is used whose secondary winding is split equally into two halves with a common centre tapped connection, (C). This configuration results in each diode conducting in turn when its anode terminal is positive with respect to the transformer centre point C producing an output during both half-cycles, twice that for the half wave rectifier so it is 100% efficient

The full wave rectifier circuit consists of two power diodes connected to a single load resistance (RL) with each diode taking it in turn to supply current to the load. When point A of the transformer is positive with respect to point C, diode D1 conducts in the forward direction as indicated by the arrows.

When point B is positive (in the negative half of the cycle) with respect to point C, diode D2 conducts in the forward direction and the current flowing through resistor R is in the same direction for both half-cycles. As the output voltage across the resistor R is the phasor sum of the two waveforms combined, this type of full wave rectifier circuit is also known as a “bi-phase” circuit.

Hope this helps you the best!

HARE KRISHNA

Answer 2

$\huge \mathfrak \red{Answer}$

>> During first half cycle of input, one diode will act as forward biased and conduct, while other diode which is reverse biased will not conduct. In other half cycle of input signal, the reverse biased diode will get forward biased and hence will conduct while other diode gets reverse biased and will not conduct. In such case, we will achieve unidirectional output voltage for positive and negative half cycle.

(SEE THE ATTACHMENT 1 & 2)

:)