Question

With the help of diagram describe in brief the Rutherford’s alpha particle scattering​

Answer 1

Answer:

Rutherford passed beams of alpha particles through a thin gold foil to observe the atom and noted how the alpha particles scattered from the foil.

Observations of Rutherford's alpha ray scattering experiment:

1.Most of the α-particles passed straight through the gold foil without any deviation.

2. Some of the α-particles were deflected by the foil by some angles.

3.Interestingly one out of every 12,000 alpha particles appeared to rebound

Conclusion of Rutherford's scattering experiment:

1.Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected.

2. Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.

3. A very small fraction of α-particles were deflected by very large angles, indicating that all the positive charge and mass of the gold atom were concentrated in a very small volume within the atom.

Explanation:

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Answer 2

Answer:

Rutherford took a very thin gold foil and bombared it with alfa - particles. He observed that:

(i) Most of the fast moving a - particles passed straight through the gold foil.

(ii) Some of the alpha particles were deflected by the foil by small angle.

(iii) Out of every 12000 particles, one appeared to rebound.

From the above observations be concluded:

(i) There is a positively charged centre in an atom called the nucleus. Nearly all mass of an atom resides in the nucleus.