with the help of first law of thermodynamics and H=U +PV prove delta heat =qp
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The enthalpy is defined by H = E + pV for a change in the states of system
ΔH = Δ (E + pV)
= ΔE + Δ (pV)
= ΔE + pΔV + VΔp ....(i)
1st law of thermodynamics states that
ΔE = q + W = q - pΔV ....(ii)
From equations (i) and (ii)
ΔH = q - pΔV + pΔV + VΔp
= q + VΔp
When the pressure is constant, Δp = 0, and thus VΔp = 0, therefore
ΔH = q (at constant pressure)
or, ΔH = qP
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