Question

With the help of graph prove 2nd equation of motion S = ut + 1/2at^2.​

Answer 1

At t =0, initial velocity = u =OA

At t = t, final velocity = v =OC

The distance S travelled in time t

t = area of the trapezium OABD

S= (1/2) × (OA + DB) × OD

S = (1/2) ×(U + V) × t

Since V= U + AT,

S=(1/2) ×(U +U + AT) ×T

S = UT + (1/2)at²

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Answer 2

Answer:

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