Question

With the help of punnett square find the percentage of heterozygous individual in f2 copulation in a cross involving a true breeding pea plant with green pads and a true breeding pea plant with yellow pods respectively

Answer 1

ANSWER:

The percentage of heterozygous individual in f2 copulation is 50%

EXPLANATION:

Let green pads be B

Let Yellow pads be b

The punnett square shows F2 generation with 3:1 ratio phenotype with 25%  as BB , 50 % bB and bb of 25% and dihybrid with 9:3:3:1 ratio phenotype on a cross involving a true breeding pea plant with 'green pads' and the true breeding pea plant with 'yellow pods' respectively.

The punnet square is square diagram which predict the "genotypes of a particular cross" or "breeding experiment". It was named after Reginald C. Punnet. This helps in determining an offspring with particular genotype.