With the help of ruler and compass only , construct a quadrilateral ABCD in which AB = 5cm , BC = 5.5 cm , AD = 4cm and Angle A = 60° and Angle B = 90°
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Step-by-step explanation:
Steps :
(i) draw AB = 5 cm.
(ii) Now draw ∠XAB such that it is 90∘.
(iii) taking A and B as a ceentre and radus 2.5 cm and 5.5 cm draw arcs cuts off at C.
(iv) Now join BC and AC.
(v) Taking C as a centre and radius 6 cm draw arcs at D on AX.
ABCD is the required quadriateral.
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I think above ans is correct
Step-by-step explanation:
best of luck
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