With the help of 't' test find whether significant difference exists in the scores obtained by the two groups of students on achievement motivation.GroupA:34,45,44,34,56,54,34,45,67,54 & GroupB:13,15,14,16,15,12,12,15,23,17
Answers
GroupA: 34,45,44,34,56,54,34,45,67,54
n = 10
Sum = 34 + 45 + 44 + 34 + 56 + 54 + 34 + 45 + 67 + 54 = 467
Mean = 467/10 = 46.7
S₁ = 11.07 Standard deviation
S₁² = 122.46 (sample variance)
GroupB: 13,15,14,16,15,12,12,15,23,17
Sum = 13 + 15 + 14 + 16 + 15 + 12 +12 + 15 + 23 + 17 = 152
Mean = 152/10 = 15.2
S₂ = 3.19 Standard deviation
S₂² = 10.18 (sample variance)
t value = (mean 1 - mean2)/(Sp (√(2/n))
n = 10
mean 1 = 46.7
Mean 2= 15.2
Sp = Polled sample variance = √((S₁² + S₂²)/2)
Sp = √((122.46 + 10.18)/2 ) = √66.32 = 8.14
t = (46.7 - 15.2) / (8.14 * (√2/10))
t = 31.5/3.64
t = 8.65
Answer:
It includes the study where it could carry out null hypothesis to find out the “t” test value.
In which, it is randomly selected groups are observed and the results are rising with the results.
A null hypothesis can only be rejected at the 5% significance level if and only if 34.6. 18. 17. 22. 63. Med-High. 13. 16. 11. 16. 56. High. 8. 14. 15. 9. 46.