Psychology, asked by kartiksharma5235, 1 year ago

With the help of 't' test find whether significant difference exists in the scores obtained by the two groups of students on achievement motivation.GroupA:34,45,44,34,56,54,34,45,67,54 & GroupB:13,15,14,16,15,12,12,15,23,17

Answers

Answered by amitnrw
15

GroupA: 34,45,44,34,56,54,34,45,67,54

n = 10

Sum = 34 + 45 + 44 + 34 + 56 + 54 + 34 + 45 + 67 + 54 = 467

Mean = 467/10 = 46.7

S₁ = 11.07  Standard deviation

S₁² = 122.46 (sample variance)

GroupB: 13,15,14,16,15,12,12,15,23,17

Sum = 13 + 15 + 14 + 16 + 15 + 12 +12 + 15 + 23 + 17 = 152

Mean = 152/10 = 15.2

S₂ = 3.19  Standard deviation

S₂² = 10.18  (sample variance)

t value =  (mean 1 - mean2)/(Sp (√(2/n))

n = 10

mean 1 = 46.7  

Mean 2= 15.2

Sp = Polled sample variance = √((S₁² + S₂²)/2)

Sp = √((122.46 + 10.18)/2 ) = √66.32 = 8.14

t = (46.7 - 15.2) / (8.14 * (√2/10))

t = 31.5/3.64

t = 8.65

Answered by Sidyandex
0

Answer:

It includes the study where it could carry out null hypothesis to find out the “t” test value.

In which, it is randomly selected groups are observed and the results are rising with the results.  

A null hypothesis can only be rejected at the 5% significance level if and only if 34.6. 18. 17. 22. 63. Med-High. 13. 16. 11. 16. 56. High. 8. 14. 15. 9. 46.

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