Question

With the help of the following equations find the value of 9xyzp1q2r3
a. 16 - 5x = 8 - 7
b.6y-7/3y+9 = 1/3
c. 2z + 5/3 = 26/3-2
d. r + 3/10r = 13/10
e. 4(q+4) = 5(q+2)
f. 3(p+10) + 200 = 236

Answer 1

Answer:

Step-by-step explanation:.(a):-3,

Answer 2

Step-by-step explanation:

a. 16 - 5x = 8 - 7

16 - 5x = 1

16 - 1 = 5x

15 = 5x

5x = 15

x = 3

b. 6y - 7/3y + 9 = 1/3

3(6y - 7) = 1(3y + 9)

18y - 21 = 3y + 9

18y - 3y = 21 + 9

15y = 30

y = 30/15

y = 2

c. 2z + 5/3 = 26/3 - 2

2z = 26/3 - 5/3 - 2

2z = 26 - 5 - 6/3

2z = 15/3

2z = 5

z = 5/2

d. r + 3/10r = 13/10

10r + 3r/10 = 13/10

13r/10 = 13/10

r = 13/10 × 10/13

r = 1

e. 4(q + 4) = 5(q + 2)

4q + 16 = 5q + 10

16 - 10 = 5q - 4q

6 = q

q = 6

f. 3(p + 10) + 200 = 236

3p + 30 + 200 = 236

3p + 30 = 236 - 200

3p + 30 = 36

3p = 36 - 30

3p = 6

p = 2

Then, putting the values of

x = 3

y = 2

z = 5/2

r = 1

q = 6

p = 2

in 9xyzp1q2r3

9.3.2.5/2.2.1.6.2.1.3 {. = ×(multiply)}

ON SOLVING

we get 9720.

So the answer is : 9720