Question

with the hep of quadratic formula solve each of the following equation.
2x/x-4 + 2x-5/x-3 = 25/3​

Answer 1

Answer:

Given

(x−4)

2x

+

(x−3)

2x−5

=

3

25

\implies \frac{2x(x-3)+(2x-5)(x-4)}{(x-4)(x-3)} = \frac{25}{3}⟹

(x−4)(x−3)

2x(x−3)+(2x−5)(x−4)

=

3

25

\implies \frac{2x^{2}-6x+2x^{2}-5x-8x+20}{x^{2}-7x+12} = \frac{25}{3}⟹

x

2

−7x+12

2x

2

−6x+2x

2

−5x−8x+20

=

3

25

\implies \frac{4x^{2}-19x+20}{x^{2}-7x+12} = \frac{25}{3}⟹

x

2

−7x+12

4x

2

−19x+20

=

3

25

\implies 3(4x^{2}-19x+20) = 25(x^{2}-7x+12)⟹3(4x

2

−19x+20)=25(x

2

−7x+12)

\implies 12x^{2} - 57x + 60 = 25x^{2}-175x+300⟹12x

2

−57x+60=25x

2

−175x+300

\implies 0 = 25x^{2}-175x+300 - 12x^{2} + 57x - 60⟹0=25x

2

−175x+300−12x

2

+57x−60

\implies 13x^{2}-118x+240 = 0⟹13x

2

−118x+240=0

please follow me

mark as a Brainliest