Question

With the usual notations prove that,

sin (A-B) a^2-b^2
---------- = -------------
sin(A+B) c^2​

Answer 1

Answer:

here we go

Step-by-step explanation:

Use Prove sin(A+B)sin(A−B)=sin2A−sin2Bsin⁡(A+B)sin⁡(A−B)=sin2⁡A−sin2⁡B

and sin(A+B)=sin(π−C)=?sin⁡(A+B)=sin⁡(π−C)=?

and Sine Law

sin(A−B)sin(A+B)=sinAcosB−sinBcosAsinAcosB+sinBcosA=2accosB−2bccosA2accosB+2bccosA=(a2−b2+c2)−(−a2+b2+c2)(a2−b2+c2)+(−a2+b2+c2)=a2−b2c2

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