Math, asked by armaan8068, 5 months ago

With this thought, students of GBSSS Pitampura decided to go for this nobel cause.
From the list of 80 students of class 11, it was found that:
30 adopted at least one dog
42 adopted at least one cat
21 adopted atleast one other pet
20 adopt dogs and cats
10 adopt cats and other pets
08 adopt dogs and other pets
5 adopt all three types of pets
On the basis of above information, answer the following questions:
a) How many students dogs and cats but no other pet?
a) 5
b) 10
c) 15
d) None of these
b) How many students adopted only dogs?
a) 5
b) 6
c) 7
d) None of these
c) How many students have not adopted a pet at all?
a) 5
b) 10
c) 15
d) 20
d) How many students other pets and have dogs or cats but not both?
a) 8
b) 11
c) 16
d) 18​

Answers

Answered by bson
0

Step-by-step explanation:

a)dogs and cats but no other pets

n(d n c)-n(dncno) =20-5=15

b)only dogs

n(d)-n(dnc)-n(dno)+n(dncno)=30-20-8+5 =7

c)no pets

n(d UcUo)= n(d)+n(c)+n(o)-n(d n c)-n(d n o)-n(onc) +n(dncno)

=60

total students -n(d UcUo)= 80-60=20

d)students having other pets and dogs or cats not both

3+5=8 from diagram

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