With what acceleration a platform descends downwards so that a block of mass 'm' placed on it experiences a normal reaction of a)Mg/4 b)0
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On drawing the free body diagram of Block,you'll realise
Mg-N=Ma
if N would be Mg/4
then it would be
Mg-Mg/4=Ma
3Mg/4=Ma
a=3g/4
b)for N to be 0
Mg-0=Ma
a=g
Mg-N=Ma
if N would be Mg/4
then it would be
Mg-Mg/4=Ma
3Mg/4=Ma
a=3g/4
b)for N to be 0
Mg-0=Ma
a=g
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