Question

With what acceleration 'a' should the box of figure (5-W4)
descend so that the block of mass M exerts a force
Mg/4 on the floor of the box ?
.
.
plz explain detail solution ​

Answer 1

As we know from Newton's second law of motion, F = M × a.

So, a = F/M

or, a =

$\frac{Mg}{4} \times \frac{1}{M}$

or, a = g/4

Answer 2

Answer:

hyy mate here is your answer

As we know from Newton's second law of motion, F = M × a.

So, a = F/M

or, a =

\frac{Mg}{4} \times \frac{1}{M}

4

Mg

×

M

1

or, a = g/4