Question

With what acceleration 'a' should the
box of figure moving up so that the block
of mass M exerts a force 7 Mg/4 on the
floor of the box?
(a) g/4
(b) g/2
(c) 3g/4
(d) 4g​

Answer 1

Answer:

c ) 3g/2 accordin to the formula

Answer 2

Answer:

C

Explanation:

We observe the block inside the lift there will be a pseudo force equal to ma on block downwards , so net force he exerts on floor

$= mg + ma = \frac{7mg}{4} \\ \implies \\ ma = \frac{7mg}{4} - mg = \frac{3mg}{4} \\ \\ a = \frac{3g}{4}$