Question

- With what horizontal velocity should a body
be thrown so that it may move parallel to the
surface of the earth along the equator? The
radius of the earth at the equator is 6400 km and
8 = 9.7 m/s​

Answer 1

Answer:

$\displaystyle{v=7.879 \ m/sec}$

Explanation:

Given ;

Radius of earth ( R ) = 6400 km

Acceleration due to gravity at surface ( g ) = 9.7 m / sec²  or 0.0097 km / sec

Let the velocity of v m / sec

Now ;

Weight = Centripetal Force

$\displaystyle{mg=\frac{mv^2}{R}}\\\\\displaystyle{g=\frac{v^2}{R}}$

Putting values here ;

$\displaystyle{0.0097=\frac{v^2}{6400}}\\\\\displaystyle{v^2=0.0097\times6400}\\\\\displaystyle{v^2=62.08}\\\\\displaystyle{v=\sqrt{62.08} \ km/sec}\\\\\displaystyle{v=7.879 \ km/sec}$

Thus we get Horizontal velocity .