Question

With what speed in miles/hr (1 m/s = 2.23 mi/hr) must an object be thrown to reach a height of 91.5
m (equivalent to one football field)? Assume negligible air resistance.

Answer 1

Final velocity(v)² - Initial Velocity(u)² = 2 * acceleration due to gravity(g) * height(h)
While the object will attain its maximum height the final velocity will be 0 m/s
0² - u² = 2 * -9.8 * 91.5
-u² = -1793.4
u² = 1793.4
u = √1793.4
u = 42.35(appx)m/s
=42.35 * 2.23 mi/s
=94.44 mi/s(appx)