With what speed must a ball be thrown down for it bounce 15m higher than its original level? Neglect any loss of energy in striking the ground.
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1/2 mu.u + mgh =mg( h + 10)
1/2mu.u +mgh=mgh+10mg
1/2 u.u =10g
u.u=20g
u=14
1/2mu.u +mgh=mgh+10mg
1/2 u.u =10g
u.u=20g
u=14
Answered by
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Hey User
BY Energy conservation law
mg(h+15) = mgh + 1/2mv²
gh + 15 g = gh + 1/2v²
15g = 1/2v²
30g = v²
v = √30g
v = √(30 x 9.8)
v = 17.14 m/s
BY Energy conservation law
mg(h+15) = mgh + 1/2mv²
gh + 15 g = gh + 1/2v²
15g = 1/2v²
30g = v²
v = √30g
v = √(30 x 9.8)
v = 17.14 m/s
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