Question

with what speed must a ball be thrown vertically up in order to rise a maximum height of 45mand for how far will it be there

Answer 1

Answer:

29.67m/s , 3.02s (I'm not very sure)

Explanation:

u= ?

v= 0

s= 45m

assuming g= 9.8m/s²

v²=u²+2(-g)s

0= u²+ 2*-9.8*45

u²= 19.6*45

=882

u= √882= 29.67m/s

v= u + (-g)t

0 = 29.67 - 19.6t

t= 29.67/19.6= 1.51 s

time of flight = 1.51*2

=    3.02s

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