Question

with what speed must a ball be thrown vertically up in order to rise to amaximum height of 53.7m

Answer 1

hi buddy
here's your answer looking for

we know that ,

${v}^{2} - {u}^{2} = 2gh$
now,

here, v=0

g= 10m/s^2

h = 53.7

so,

$= > {0}^{2} - {u}^{2} = 2 \times 10 \times 53.7 \\ \\ = > - {u }^{2} = - 1074 \\ \\ = > u = \sqrt{1074} = 32.77m {s}^{ - 1}$
hope you are satisfied with my answer

Answer 2

Answer is 32.7719

u=?
v=0 as at the highest point velocity will become 0
a=-10m/s^2 its always negative as the direction is downwards
s=h=53.7m.

v^2=u^2+2as
0=u^2+2*-10*53.7
-u^2=-20*53.7
therefore, u=√1074
u=32.7719


Hope you would be satisfied with my answer.