Question

with what speed should a body be thrown upwards so that the distances traversed in 5th second and 6th second are equal?​

Answer 1

Explanation:

This is only possible if the ball stops moving post 5th second and starts downward journey at start of 6th second. In this case the distance covered in 5th and 6th sec are same, also in 4th and 7th are same, 3rd and 8th too, then 2nd and 9th and finally cover maximum distance amongst all in 1st or 10th sec.

Considering above situation the ball reached maximum height in 5 secs. Therefore using the equation

0 = u - g(5) …… { v = u + at }

u = 5g = 5*9.8 = 49 m/s

This is the speed you must throw with to get distance covered in 5th and 6th sec to be same.