Question

Without actaual division show that 18 is a factor of 18018

Answer 1

Answer:

Step-by-step explanation:

For this we need to check the divisibility test of 18 means check it with 2 and with 9

For 2 just check whether it is a even no. or not.

For 9 see that the sum of digit of no. is divisible by 9

Answer 2

Hey,

We need to apply the divisibility test of both 2 and 9, because if it is divisible by both 2 and 9 then it will be divisible by 18.

now the sum of the digits of 18018 = 1 + 8 + 0 + 1 + 8 = 18

Hence it is divisible by 9 (Since the sum of the digits is divisible by 9).

Also, it is divisible by 2 because the last digit here, i.e. 8 is divisible by 2.

Therefore 18018 is divisible by both 2 and 9, so it is also divisible by 18.