Without actual calculating the cubes find the value of 1 by 2 whole cube + 1 by 3 whole cube minus 5 by 6 whole cube
Answers
Answered by
216
Hi ,
*************************************
If x + y + z = 0 then
x³ + y³ + z³ = 3xyz
*********************************************
Here ,
x = 1/2 ,
y = 1/3 ,
z = - 5/6
x + y + z
= 1/2 + 1/3 - 5/6
= ( 3 + 2 )/6 - 5/6
= 5/6 - 5/6
= 0 ,
Therefore ,
x³ + y³ + z³
= ( 1/2 )³ + ( 1/3 )³ + ( -5/6 )³
= 3 × ( 1/2 ) × ( 1/3 ) × ( -5/6 )
= - ( 3 × 5 )/ ( 2 × 3 × 6 )
= -5/12
I hope this helps you.
: )
*************************************
If x + y + z = 0 then
x³ + y³ + z³ = 3xyz
*********************************************
Here ,
x = 1/2 ,
y = 1/3 ,
z = - 5/6
x + y + z
= 1/2 + 1/3 - 5/6
= ( 3 + 2 )/6 - 5/6
= 5/6 - 5/6
= 0 ,
Therefore ,
x³ + y³ + z³
= ( 1/2 )³ + ( 1/3 )³ + ( -5/6 )³
= 3 × ( 1/2 ) × ( 1/3 ) × ( -5/6 )
= - ( 3 × 5 )/ ( 2 × 3 × 6 )
= -5/12
I hope this helps you.
: )
Answered by
28
Answer:
the answer is minus 5 by 12
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