Question

Without actual calculating the cubes, find the value of each of the following
(i) (-10)^3 + (7)^3 + (3)^3
(ii) (28)^3+(-15)^3 + (-13)^3
(iii)(1/2)^3+(1/3)^3-(5/6)^3
(iv) (0.2)^3 - (0.3)^3 + (0.1)^3
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Answer 1

Answer:

(-10+7+3)^3=0

(28-15-13)^3=0

(1/2+1/3-5/6)^3=0

(0.2+0.1-0.3)^3=0