without actual calculating the cubes,find the value of each of the following 1. ( -10)cube +(7)cube +(3)cube
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10
a+b+c = 0, a3+b3+c3=3abc hence, a=(-10) ,b= 7, c=3 now ,(-10)3+ (7)3 +( 3)3 = 3×(-10)× 7 ×3 = -630
pranayreddy78:
i want with process
Answered by
13
whenever (a+ b + c) = 0,
a³ + b³ + c³ = 3abc
therefore, taking a= -10 , b= 7 , c= 3
Eq. formed will be :
3abc = 3 x -10 x 7 x 3
= -630
a³ + b³ + c³ = 3abc
therefore, taking a= -10 , b= 7 , c= 3
Eq. formed will be :
3abc = 3 x -10 x 7 x 3
= -630
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