Question

Without actual calculation find :
(-12)^3+(7)^3+(5)^3

Answer 1

=-12+7+5

=-12+12

=0

$using \: identity$

$if \: a + b + c = 0 \: then \: a {}^{3} + b {}^{3} + c {}^{3} = 3abc$

So:-

(-12)^3+(7)^3+(5)^3 :-

3abc= 3(-12)(7)(5)

Answer 2

$\huge \boxed{ \mathfrak \red{sol}}$

If a + b + c = 0 then a³ + b³+ c³= 3abc ifa+b+c=0

-12+7+5

=-12+12

=0

$\therefore$

3×(-12)³+(7)³+(5)³

3abc= 3(-12)(7)(5)

$\huge\boxed{ \mathfrak \purple{= -1260}} \:$