Question

without actual calculation find the cubes (0.2)^3+(-0.3)^3+(0.1)^3

Answer 1

(0.2)^3 + (-0.3)^3 +(0.1)^3

here a =0.2 ,b= -0.3 ,c= 0.1

if a + b + c =0

0.2 +(-0.3) + 0.1 =0

0.3 - 0.3 =0

then, a^3 + b^ + c^3 = 3 abc

= 3( 0.2) (-0.3)(0.1)

= -0.018

hope it helps

Answer 2

Answer is in Attachment !