Without actual calculations evaluate. (28)3+(-15)3+(-13)3
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3(28-15-13)=3*0=0
the result is 0 because when we take 3 as common then the summation in the bracket will be 0.
the result is 0 because when we take 3 as common then the summation in the bracket will be 0.
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0 take 3 common and rest all terms get cancelle
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