Question

without actual calucating the cubes,find the value if each of the following(-10)^3+(7)^3+(3)^3​

Answer 1

Answer:

-10+7+3=0

so,a3+b3+c3=3abc

=3(-10)(7)(3)

=21(-30)

=-630 ans

Answer 2

Answer:

-630

Step-by-step explanation:

(-10)³+7³+3³=(-10)³+(7+3)*(7²-3×7+3²)

=(-10)³+10*37

=-10{(-10)²-37}

=-10(100-37)

=-10*63

=-630

Used (a³+b³)=(a+b)(a²-ab+b²)