Question

without actual division,find remainder obtained on dividing 3x²+5x-9 by (3x+2)

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Answer 1

Answer:

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Answer 2

$3x + 2 = 0 \\ 3x = - 2 \\ x = \frac{ - 2}{3} \\ 3( \frac{4}{9} ) + 5( \frac{ - 2}{3} ) - 9 = \frac{4}{3} - \frac{10}{3} - 9 \\ = \frac{ - 6}{3} - 9 = - 2 - 9 = - 11$

remainder is -11

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