Question

Without actual division find the remainder when (3x²+5x-9) is divided by (3x + 2)

Answer 1

Given:

(3x²+5x-9)

To find:

The remainder when (3x²+5x-9) is divided by (3x + 2).

Solution:

1) (3x²+5x-9) is divided by (3x + 2) we can simply solve this putting the value of x from (3x + 2) to the given polynomial.

2)To get the value of x

Put the (3x + 2) = 0

• x = -2/3

3) Putting the value of x in (3x²+5x-9)

• (3x²+5x-9)
• 3(-2/3)²+5(-2/3)-9
• 3×4/9 - 10/3 - 9
• 4/3 - 10/3 - 9
• -6/3 -9
• -2-9
• -11

The remainder when (3x²+5x-9) is divided by (3x + 2) is -11.