Without actual division find the remainder when 3x4-4x3-3x-1 is divided by x+1
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Solution:
3x³-7x²+7x-11
x+1)3x⁴-4x³-3x-1(3x³-7x²+7x-11
**** 3x⁴+3x³
_______________
*******-7x³+0
****** -7x³-7x²
_______________
***********7x²-3x
********** 7x²+7x
__________________
***************-11x-1
*************** -11x-11
_______________________
********Remainder (10)
Therefore,
Dividend = 3x⁴-4x³-3x-1
Divisor = x+1
quotient = 3x³ - 7x² +7x -11
Remainder = 10
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