Question

Without actual division, find the remainder when 3y^4-8y^3-y^2-5y-5 is divided by (y-3)

Answer 1

Substitute y = 3

3 (3)⁴- 8 (3)³- 3²-5(3)-5 = 243 - 216 -9-15-5 = -2

You will get - 2 which is the remainder

Answer 2

Hello Dear!!!

Here's your answer....

Let,

f(x) = 3y^4-8y^3-y^2-5y-5

Zero of (y-3) is

y-3 = 0

y = 3

substitute the value of y

3y^4-8y^3-y^2-5y-5

3(3)^4 - 8(3)^3 - (3)^2 - 5(3) - 5

3(81) - 8(27) - 9 - 15 - 5

243 - 216 - 9 - 15 - 5

-2.

The remainder is -2.

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Hope this helps you...