Question

Without actual division find whether the rational number 1323/6*6*6*35*35 has a terminating or non terminating and repeating decimal

Answer 1

Answer:

Step-by-step explanation:

1323 / 6*6*6*35*35

= 1323/ 2×2×2×3×3×3×5×5×7×7

= 441 / 2×2×2×3×3×5×5×7×7

= 147/ 2×2×2×3×5×5×7×7

=49 / 2×2×2×5×5×7×7

= 1/2^3×5^2

Since the denominator is in the form of 2^m×5^n

The decimal expansion is terminating one..

Answer 2

$\sf \pmb{Answer :}$

Step-by-step explanation:

1323 / 6*6*6*35*35

= 1323/ 2×2×2×3×3×3×5×5×7×7

= 441 / 2×2×2×3×3×5×5×7×7

= 147/ 2×2×2×3×5×5×7×7

=49 / 2×2×2×5×5×7×7

= 1/2^3×5^2

Since the denominator is in the form of 2^m×5^n

The decimal expansion is terminating one..